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02-12-2018
Mathematics

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how to solve for area of triangle where A=67 degrees, b=11yd, and c=24yd

Respuesta :

02-12-2018

Use the formula of an area of a tringle:

[tex]A=\dfrac{1}{2}bc\sin A[/tex]

We have b = 11 yd, c = 24 yd and m∠A = 67°

[tex]A=\dfrac{1}{2}(11)(24)\sin67^o[/tex]

[tex]\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2[/tex]

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