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  • 03-02-2019
  • Mathematics
contestada

The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area of the triangle?

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calculista
calculista calculista
  • 12-02-2019

Answer:

The area of triangle is [tex]8 \frac{1}{3}\ m^{2}[/tex]

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

[tex]\sqrt[4]{16}=(2^{4})^{1/4}=2[/tex]

so

h=2 m

substitute

[tex]A=(1/2)(25/3)2=25/3\ m^{2}[/tex]

convert to mixed number

[tex]25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}[/tex]

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