bjshivers2422 bjshivers2422
  • 03-04-2019
  • Mathematics
contestada

Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

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frika
frika frika
  • 03-04-2019

Answer:

[tex]\dfrac{y^2}{36}-\dfrac{x^2}{45}=1.[/tex]

Step-by-step explanation:

Since vertices and foci lie on the y-axis, the equation of the hyperbola is

[tex]\dfrac{y^2}{b^2}-\dfrac{x^2}{a^2}=1.[/tex]

If the vertices are at points (0,±6), then [tex]b=6.[/tex]

If the foci are at points (0,±9), then [tex]c=9.[/tex]

Note that

[tex]c^2=b^2+a^2,[/tex]

then

[tex]9^2=6^2+a^2,\\ \\a^2=81-36,\\ \\a^2=45.[/tex]

The equation of the hyperbola is

[tex]\dfrac{y^2}{36}-\dfrac{x^2}{45}=1.[/tex]

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