jordanrials093 jordanrials093
  • 04-01-2020
  • Mathematics
contestada

(i wont ask anymore after this)
How many solutions does each equation have? a) 7(2+5v)=3v+14 b) -3 (3-6b)=6b+5 c) 2 (a-2)=2a-4

Respuesta :

kenlingdad kenlingdad
  • 04-01-2020

Answer:

a) v = 0

b) b = 7 / 6

c) a = any number

Step-by-step explanation:

a)    7(2+5v)=3v+14

     7 x 2 + 7 x 5v = 3v + 14  .... distributive

     14 + 35v = 3v + 14

     35v - 3v = 14 - 14

      32v = 0

      v = 0 ...... only v value can fit  

b) -3 (3-6b)=6b+5

   -9 + 18b = 6b + 5

   18b - 6b = 5 + 9

   12b = 14

    b = 14 / 12 = 7 / 6

c) 2 (a-2)=2a-4

    2a - 4 = 2a - 4

    2a -4 + 4 = 2a -4 + 4

    2a = 2a

     a = a ........ a cab be any number

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