yanhuiluzhang yanhuiluzhang
  • 04-04-2020
  • Mathematics
contestada

Factor 1.21a^6+22a^3+100

Respuesta :

Hrishii
Hrishii Hrishii
  • 04-04-2020

Answer:

[tex] \frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100) [/tex]

Step-by-step explanation:

[tex]1.21 {a}^{6} + 22 {a}^{3} + 100 \\ = 1.21 {a}^{6} + 11 {a}^{3} + 11 {a}^{3}+ 100 \\ = 11 {a}^{3} (0.11 {a}^{3} + 1) + 100(0.11 {a}^{3} + 1) \\ = (0.11 {a}^{3} + 1) (11 {a}^{3} + 100) \\ = ( \frac{11}{100} {a}^{3} + 1) (11 {a}^{3} + 100) \\ = ( \frac{11{a}^{3} + 100}{100} ) (11 {a}^{3} + 100) \\ = \frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100) \\ are \: the \: required \: factors.[/tex]

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