The answer is option B. -4.5°C or 268.5 kelvin.
freezing point depression = 1.86 ° C kg/mol.
molality = 0.80 mol / 1.00 kg
T= (K ) (molality)
T = 1.86 * 0.86
The freezing point of water in kelvin is 273.15 k. The relation between Celsius and Kelvin scales of temperature is TKelvin = TCelsius + 273.15. The freezing point of water in Celsius is 0 °C; hence, the freezing point is 273.15 Kelvin scale.
Learn more about depression in freezing point here:-https://brainly.com/question/17048792
#SPJ2