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  • 03-05-2020
  • Mathematics
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In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What was the resulting population?

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  • 03-05-2020

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> [tex]\frac{15}{100}[/tex] -> 0.15

Next, multiply 4,000 by 0.15:

[tex]x= 4,000(0.15)[/tex]

[tex]x=600[/tex]

The last step is to add the 600 back to 4,000:

[tex]4,000 + 600 = 4,600[/tex]

The population of Smallburg the following year was 4,600.

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