Respuesta :

taniaorozco
the maximum value of the function is 5/4.
[tex]\bf \stackrel{f(x)}{y}=1-x-x^2\implies y=-x^2-x+1 \\\\\\ \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{lccclll} y = &{{ -1}}x^2&{{ -1}}x&{{ +1}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right) \\\\\\ \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad \stackrel{maximum}{1-\cfrac{(-1)^2}{4(-1)}}\right)[/tex]

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