manglefox0327
manglefox0327 manglefox0327
  • 01-07-2018
  • Mathematics
contestada

Find the number of real number solutions for the equation. x^2+0x-1=0

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mathstudent55
mathstudent55 mathstudent55
  • 01-07-2018
x^2 + 0x - 1 = 0

x^2 - 1 = 0

This is a difference of two squares which factors into the product of a sum and a difference with the pattern: a^2 - b^2 = (a + b)(a - b).

(x + 1)(x - 1) = 0

x + 1= 0  or  x - 1 = 0

x = -1  or  x = 1

Answer: There are two real solutions.
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konrad509
konrad509 konrad509
  • 01-07-2018
[tex]x^2+0x-1=0 \\ x^2-1=0\\ x^2=1\\ x=-1 \vee x=1[/tex]
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