From the given diagram, using the property of similar Triangle we can write
[tex] \\\\frac{60}{60+27}=\frac{80}{80+2x}\\\\\\frac{60}{87}=\frac{80}{80+2x}\\\\\Rightarrow 60(80+2x)=80*87\\\\\\Rightarrow 80+2x=116\\\\\Rightarrow x=18\\ [/tex]
