Respuesta :

austint1414

x^2+4x-4=8

Subtract 8 from both sides: x^2+4x-4-8=8-8

Simplify: x^2+4x-12=0

Solve with the quadratic formula: For a=1,b=4,c=-12: x1,2= -4+- (4^2-4*1(-12))sqrt over 2*1

x= 2 and x=-6

The value of x is -6 and 2.

Given that,

  • The equation is [tex]x^2 + 4x - 4 = 8[/tex].

Based on the above information, the calculation is as follows:

[tex]x^2 + 4x - 4 = 8\\\\ x^2 +4x -12 = 0\\\\ (x + 6) (x - 2) = 0\\\\ [/tex]

x = -6 and 2

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