Answer:
[tex]\large\boxed{A.\ \dfrac{1}{x^2y^2}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x^0y^{-3}}{x^2y^{-1}}=\dfrac{1\cdot\dfrac{1}{y^3}}{x^2\cdot\frac{1}{y}}=1\cdot\dfrac{1}{y^3}\cdot\dfrac{1}{x^2}\cdot\dfrac{y}{1}=\dfrac{1}{y^2x^2}[/tex]
[tex]\text{Used}\\\\a^0=1\ \text{for all real numbers except 0}\\\\a^{-n}=\dfrac{1}{a^n}[/tex]
