Answer:
17.3124 grams
Explanation:
Given;
Amount of heat to be produced = 175 kJ
Molar mass of the carbon monoxide = 12 + 16 = 28 grams
Now,
The standard molar enthalpy of carbon monoxide = 283 kJ/mol
Thus,
To produce 175 kJ heat, number of moles of CO required will be
= Amount heat to be produced / standard molar enthalpy of CO
or
= 175 / 283
= 0.6183
Also,
number of moles = Mass / Molar mass
therefore,
0.6183 = Mass / 28
or
Mass of the CO required = 0.6183 × 28 = 17.3124 grams
