emihig4519 emihig4519
  • 02-05-2020
  • Mathematics
contestada

Suppose you want to factor the expression x2+ 2xn+n2. Given that n> 0, what are the factors? Explain.

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mirai123
mirai123 mirai123
  • 02-05-2020

Answer:

[tex]\left(x+n\right)^2=(x+n)(x+n)[/tex]

Step-by-step explanation:

[tex]\:x^2+\:2xn+n^2[/tex]

[tex]\mathrm{Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2[/tex]

[tex]\left(x+n\right)^2=(x+n)(x+n)[/tex]

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vintechnology vintechnology
  • 25-11-2021

The factors are (x + n)(x + n)

x² + 2xn + n²

Now let's factor it

x² + 2xn + n²

2xn = xn + xn

Therefore,

x² + xn + xn + n²

x(x + n) + n(x + n)

(x + n)(x + n)

(x + n)²

read more; https://brainly.com/question/16305042?referrer=searchResults

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