jackieventura76 jackieventura76
  • 04-05-2020
  • Mathematics
contestada

the axis of symmetry for the graph of the function f(x)=3x^2+bx+4 is x= 3/2. what is the value of b

Respuesta :

PhantomWisdom PhantomWisdom
  • 09-05-2020

Answer:

b = -9

Step-by-step explanation:

The function is given as :

[tex]f(x)=3x^2+bx+4[/tex]

The axis of symmetry for this function is x = 3/2

It is required to find the value of b. The axis of symmetry of a parabola is a vertical line that intercepts its vertex at its horizontal coordinate. It can be given by :

[tex]x=\dfrac{-b}{2a}[/tex]

Putting x = 3/2 and a = 3 we get :

[tex]b=-2ax\\\\b=-2\times 3\times \dfrac{3}{2}\\\\b=-9[/tex]

So, the value of b is -9.

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