bhachumanpreet
bhachumanpreet bhachumanpreet
  • 02-10-2020
  • Chemistry
contestada

Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%
NaCl solution.​

Respuesta :

sebassandin
sebassandin sebassandin
  • 07-10-2020

Answer:

[tex]m_{solute}=26.8g[/tex]

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

[tex]\%m/m=\frac{m_{solute}}{m_{solution}}*100\%[/tex]

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

[tex]m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g[/tex]

Best regards.

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