schoolking
schoolking schoolking
  • 01-08-2021
  • Mathematics
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Would √x+6 -4 = x be an extraneous solution? The x + 6 are under the radicands line.

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saksham2007
saksham2007 saksham2007
  • 01-08-2021

[tex] \sqrt{x + 6 } = x + 4[/tex]

now square both side

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