Respuesta :

annie5gaewu

Step-by-step explanation:

group like terms

[tex]3w \geqslant 19 - 1[/tex]

solve

[tex]3w \geqslant 18[/tex]

divide the number with the variable by both sides

[tex] \frac{3w}{3} \geqslant \frac{18}{3} [/tex]

solve

[tex]w \geqslant 6[/tex]

xKavinsky

Answer:

w ≥ 6

Step-by-step explanation:

Given:

3w+1≥19

Solve:

3w+1≥19

Subtract 1 from both sides

3w+1≥19

     -1  -1

-----------------

3w≥18

Divide both sides by 3

3w/3 ≥18/3

w ≥ 6

Hence, the answer is:

w ≥ 6

Kavinsky