jacyliles343 jacyliles343
  • 03-09-2017
  • Mathematics
contestada

The product of two consecutive even integers is 288 find the integers.

Respuesta :

quenbarr quenbarr
  • 13-09-2017
using algebra
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring 288using arithmetic...√288=16.97≈1716 and 18 are the integers (as well as -16 and -18)
Answer Link

Otras preguntas

How many “dots” would be around the central atom in the Lewis structure of S? A) 5 B) 6 C) 7 D) 4
Approximately how many miles apart are Petrograd and Moscow ? A. 200 B. 350 C. 500 D. 650
What is the velocity of an object that has a mass of 2.5 kilogram and a momentum of 1,000 kg·m/sec?
what is the volume of an area? what is a polynomial?
what is the difference between closed-end credit and open-end credit
need help with this question#20
Two numbers have a product of 48 and a sum of 19 what are the numbers and how do you know
solve the following problem: (12×10^9)÷(6×10^5)
Social needs are acquired through?
Dirk Nowitzki of the Dallas mavericks scored 44 points in a recent basketball game. He scored no 3-point shots, but made a number of 2-point field goals and 1-p