jelly50 jelly50
  • 03-04-2018
  • Mathematics
contestada

evaluate 10 sigma n=2 25(0.3)^(n+1)

Respuesta :

Sarith
Sarith Sarith
  • 20-02-2019

Answer: 0.964

Step-by-step explanation:

Create a series with the "n" values starting with n=2 until n=10: 25(0.3)^(2)+1 + 25(0.3)^(3)+1 + 25(0.3)^(4)+1 + 25(0.3)^(5)+1 + 25(0.3)^(6)+1 + 25(0.3)^(7)+1 + 25(0.3)^(8)+1 + 25(0.3)^(9)+1 + 25(0.3)^(10)+1

= 0.675 + 0.2025 + 0.06075 + 0.018225 + 0.0054675 + 0.00164025 + 0.00049207 + 0.00014762 + 0.00004428

≈ 0.964

Answer Link

Otras preguntas

explain why an aqueous solution of Na2SO4 is neutral while an aqueous solution of Na2CO3 is basic in nature?
18. Which number rounds to 0.94 when rounded to the nearesthundredth?
While performing an experiment at home, Emma adds lemon juice to a soap solution. How will this affect the pH of the soap solution?The pH will remain constant.o
mixed into the batter ( was or were) a dozen of the freshest eggs.
Pitch me a short story idea. Nothing too short Nothing too long have it be simple so its like a 5th grader But not a simple as a 2nd grader. I fell asleep after
Which products are negative? Choose all answers that are correct. A. -1 1/4 · (-2 3/4) · (-3) B. 1/2 · (-1/4) · (1/8) C. 8 • (–1.1) • 5 D. –3.
Help me pleaseeeeeee
the chinese exclusion act of 1882 and the gentlemens agreement with japan in 1907 both illastrate
r to grow crops. Which of these is the biggest consequence that occurs with excessive irrigation?
what happens when a solid compound dissolves in water?