kaihalojr kaihalojr

01-05-2018
Mathematics

contestada

Solve.
2x^2 + x - 1 = 2
A 1,2
B No real solutions
C 1,-3/2
D x = (-1 plus minus 3) over 2

Respuesta :

29-07-2018

[tex]2x^2+x-1=2\ \ \ |-2\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\ \ |-3\\2x=-3\ \ \ |:2\\x=-\frac{3}{2}\\\\x-1=0\ \ \ |+1\\x=1[/tex]

Answer: C 1, -3/2

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